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Fix DOI reference and formatting in README
Updated DOI reference and improved formatting in the README.
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README.md
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README.md
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# Active CRLH Transmission Line Modeler
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# Active CRLH Transmission Line Modeler
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A MATLAB simulation of an **active Composite Right/Left-Handed (CRLH) transmission line** with a frequency-dependent negative resistance element. The structure achieves controlled gain across a user-defined passband by embedding an active shunt element (modeled as a negative resistance `Rn`) within a periodic CRLH unit cell topology.
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A MATLAB simulation of an **active Composite Right/Left-Handed (CRLH) transmission line** with a frequency-dependent negative resistance element. The structure achieves controlled gain across a user-defined passband by embedding an active shunt element (modeled as a negative resistance `Rn`) within a periodic CRLH unit cell topology.
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This is supplemental code for the paper "Negative Resistance Enabled Amplifying CRLH Transmission Lines With Uniform Insertion Gain" (https://ieeexplore.ieee.org/document/11366944)
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This is supplemental code for the paper "Negative Resistance Enabled Amplifying CRLH Transmission Lines With Uniform Insertion Gain" DOI: 10.1109/LMWT.2026.3655243 (https://ieeexplore.ieee.org/document/11366944)
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---
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---
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## Background
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## Background
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- Bloch impedance (real and imaginary)
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- Bloch impedance (real and imaginary)
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- Outputs (in command window):
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- Outputs (in command window):
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- Constituent CRLH parameters
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- Constituent CRLH parameters
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- $R_n(\omega) exponential fit parameters
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- $R_n(\omega)$ exponential fit parameters
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- $S_{21}$ at desired frequencies ($\omega_1$ and $\omega_2$)
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- $S_{21}$ at desired frequencies ($\omega_1$ and $\omega_2$)
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- Maximum gain
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- Maximum gain
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## Design Equations
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## Design Equations
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CRLH element values are solved analytically from the two phase/frequency constraints:
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CRLH element values are solved analytically from the two phase/frequency constraints in Reference [1].
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$$L_R = \frac{Z_0(\theta_1 \frac{\omega_1}{\omega_2} - \theta_2)}{n\,\omega_2\!\left(1 - \left(\frac{\omega_1}{\omega_2}\right)^2\right)}$$
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Then, the required $R_n(\omega)$ is calculated as:
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$$C_R = \frac{\theta_1 \frac{\omega_1}{\omega_2} - \theta_2}{n\,\omega_2 Z_0\!\left(1 - \left(\frac{\omega_1}{\omega_2}\right)^2\right)}$$
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$$R_n(\omega) = -R_0e^{\alpha\omega}$$
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with symmetric expressions for `LL` and `CL`.
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with
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$$\alpha = \frac{\ln{\left(\frac{R_n(\omega_1)}{R_n(\omega_2)}\right)}}{\omega_1 - \omega_2}$$,
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$$R_0 = -R_n(\omega_1)e^{-\alpha \omega_1}$$.
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This will approximately fit the exact solution of:
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$$R_n(\omega) = \frac{1 \pm \sqrt{1 - 4(G'_{sh} \omega L_L)^2}}{2G'_{sh}}$$
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The required negative resistance at each frequency satisfies:
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The required negative resistance at each frequency satisfies:
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